in pacman party each map is predefined, causing them to the the same each time. with this knowledge i created what i believe to be the optimal without too much needed luck solutions to finish each map only landing on the cookie factory twice. these solutions are not tested to see how likely the enemies will land on your castles enough for you to succeed.

notation is pretty simple, you just read each # as an individual roll example) 838(13 or 31) translation) roll an 8, then 3, then 8, then either a 1 then 3, or a 3 then 1

for world 1) 838488888 world 1 is extremely optimised because it is at the start of the game, and only has one bot

if the enemy engages more than one battle this game, restart the game, or live with it

if the enemy battles a level one castle, restart the game, or live with it

if the enemy takes a space you should have by the end of the game, restart the game

if you preform an unintended roll, restart the game

if you don't win after reaching the factory the second time restart the game

if you do not get a factory warp at the last move, roll a 78, restart the game, or quit the game using the home button; loading the game; and redoing the last turn

for world 2) 83888384836818 if you did not get a factory warp, use your intuition to win if you got to the factory a second time and didn't win, restart the game, or use your intuition to win

for world 3) 778457(7845 or 888) use 888 if the first 8 there is an untaken castle

for world 4) 834888788

for world 5) 8(8134 or 286)888 use 286 if you think the bots are not going to roll high enough to interrupt building your castle

if any boss fight occurs, restart the game if any boss is activated, use your intuition to win if any castle that should be yours at the end of the game is (not world 1) taken use your intuition to win if you roll an unintended roll (not world 1) use your intuition to win if you are transported to a new space in the map, use your intuition to win